AIPMT 2002 | Electrostatics Question 77 | Physics

AIPMT 2002

MCQ (Single Correct Answer)

-1

Identical charges ($$-$$q) are placed at each corners of cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be

$${{ - 4\sqrt 2 {q^2}} \over {\pi {\varepsilon _0}b}}$$

$${{ - 8\sqrt 2 {q^2}} \over {\pi {\varepsilon _0}b}}$$

$${{ - 4\,{q^2}} \over {\sqrt 3 \,\pi {\varepsilon _0}b}}$$

$${{8\sqrt 2 \,{q^2}} \over {4\,\pi {\varepsilon _0}b}}$$

AIPMT 2002

MCQ (Single Correct Answer)

-1

Some charge is being given to a conductor. Then its potential is

maximum at surface

maximum at centre

remain same throughout the conductor

maximum somewhere between surface and centre.

AIPMT 2002

MCQ (Single Correct Answer)

-1

A capacitor of capacity C₁ charged upto V volt and then connected to an uncharged capacitor of capacity C₂. The final potential difference across each will be

$${{{C_1}V} \over {{C_1} + {C_2}}}$$

$${{{C_2}V} \over {{C_1} + {C_2}}}$$

$$\left( {1 - {{{C_2}} \over {{C_1}}}} \right)V$$

$$\left( {1 + {{{C_2}} \over {{C_1}}}} \right)$$

AIPMT 2001

MCQ (Single Correct Answer)

-1

A dipole of dipole moment $$\overrightarrow p $$ is placed in uniform electric field $$\overrightarrow E $$ then torque acting on it is given by

$$\overrightarrow \tau = \overrightarrow p .\overrightarrow E $$

$$\overrightarrow \tau = \overrightarrow p \times \overrightarrow E $$

$$\overrightarrow \tau = \overrightarrow p + \overrightarrow E $$

$$\overrightarrow \tau = \overrightarrow p - \overrightarrow E $$