AIPMT 2002 | Properties of Matter Question 79 | Physics

AIPMT 2002

MCQ (Single Correct Answer)

-1

Consider two rods of same length and different specific heats (S₁, S₂), conductivities (K₁, K₂) and area of cross-sections (A₁, A₂) and both having temperatures T₁ and T₂ at their ends. If rate of loss of heat due to conduction is equal, then

K₁A₁ = K₂A₂

$${{{K_1}{A_1}} \over {{S_1}}} = {{{K_2}{A_2}} \over {{S_2}}}$$

K₂A₁ = K₁A₂

$${{{K_2}{A_1}} \over {{S_2}}} = {{{K_1}{A_2}} \over {{S_1}}}$$

AIPMT 2002

MCQ (Single Correct Answer)

-1

For a black body at temperature 727^oC, its radiating power is 60 watt and temperature of surrounding is 227^oC. If temperature of black body is changed to 1227^oC then its radiating power will be

304 W

320 W

240 W

120 W

AIPMT 2002

MCQ (Single Correct Answer)

-1

The Wien's displacement law express relation between

wavelength corresponding to maximum energy and temperature

radiation energy and wavelength

temperature and wavelength

colour of light and temperature.

AIPMT 2001

MCQ (Single Correct Answer)

-1

A cylindrical rod having temperature T₁ and T₂ at its end. The rate of flow of heat Q₁ cal/sec. If all the linear dimension are doubled keeping temperature constant, then rate of flow of heat Q₂ will be

4Q₁

2Q₁

$${{{Q_1}} \over 4}$$

$${{{Q_1}} \over 2}$$

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