1
MCQ (Single Correct Answer)

AIPMT 2010 Prelims

Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?
A
NaOH/Br2
B
Sodalime
C
Hot conc.H2SO4
D
PCl5

Explanation

Among the given reagents only NaOH/ Br2 converts -CONH2 group to -NH2 group. This is known as Hofmann bromamide reaction.

CH3-CONH2 + NaOH +Br2

   $$ \to $$ CH3NH2 + NaBr + Na2CO3 + H2O
2
MCQ (Single Correct Answer)

AIPMT 2009

Propionic acid with Br2/P yields a dibromo product. Its structure would be
A
B
CH2(Br) $$-$$ CH2 $$-$$ COBr
C
D
CH2(Br) $$-$$ CH(Br) $$-$$ COOH

Explanation

This is Hell–Volhard–Zelinsky reaction.
In this reaction, acids containing $$\alpha $$-H react with Br2 /red P giving product in which the $$\alpha $$-hydrogens are substituted by Br.
3
MCQ (Single Correct Answer)

AIPMT 2009

Trichloroacetaldehyde, CCl3CHO reacts with chlorobenzene in presence of sulphuric acid and produces
A
B
C
D

Explanation

4
MCQ (Single Correct Answer)

AIPMT 2008

Acetophenone when reacted with a base, C2H5ONa,   yields a stable compound which has the structure
A
B
C
D

Explanation

This reaction is known as aldol condensation.

C2H5ONa $$ \Rightarrow $$ C2H5O- + Na+

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