1
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
A rigid ball of mass m strikes a rigid wall at 60o and gets reflected without loss of speed as shown in the figure. The value of impulse imparted by the wall on the ball will be :
NEET 2016 Phase 2 Physics - Center of Mass and Collision Question 33 English
A
$$mV$$
B
2 $$mV$$
C
$${{mV} \over 2}$$
D
$${{mV} \over 3}$$
2
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
A bullet of mass 10 g moving horizontally with a velocity of 400 m s$$-$$1 strikes a wood block of mass 2 kg which is suspended by light inextensible string of length 5 m. As a result, the centre of gravity of the block found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be
A
100 m s$$-$$1
B
80 m s$$-$$1
C
120 m s$$-$$1
D
160 m s$$-$$1
3
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
Two identical balls A and B having velocities of 0.5 m s$$-$$1 and $$-$$0.3 m s$$-$$1 respectively collide elastically in one dimension. The velocities of B and A after the collision respectively will be :
A
$$-$$0.5 m s$$-$$1 and 0.3 m s$$-$$1
B
0.5 m s$$-$$1 and $$-$$0.3 m s$$-$$1
C
$$-$$0.3 m s$$-$$1 and 0.5 m s$$-$$1
D
0.3 m s$$-$$1 and 0.5 m s$$-$$1
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
Two particles of masses m1, m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy $$\varepsilon $$. If final velocities of particles be v1 and v2 then we must have :
A
$${1 \over 2}$$m1u$$_1^2$$ + $${1 \over 2}$$ m2u$$_2^2$$ $$-$$ $$\varepsilon $$ = $${1 \over 2}$$ m1v$$_1^2$$ + $${1 \over 2}$$m2v$$_2^2$$
B
$${1 \over 2}$$m$$_1^2$$u$$_1^2$$ + $${1 \over 2}$$m$$_2^2$$u$$_2^2$$ + $$\varepsilon $$ = $${1 \over 2}$$m$$_1^2$$v$$_1^2$$ + $${1 \over 2}$$m$$_2^2$$v$$_2^2$$
C
m$$_1^2$$u1 + m$$_2^2$$u2 $$-$$ $$\varepsilon $$ = m$$_1^2$$v1 + m$$_2^2$$v2
D
$${1 \over 2}$$m1u$$_1^2$$ + $${1 \over 2}$$m2u$$_2^2$$ = $${1 \over 2}$$m1v$$_1^2$$ + $${1 \over 2}$$m2v$$_2^2$$ $$-$$ $$\varepsilon $$
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