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Questions
1
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
The solution set of the system of inequalities $5-4 x \leq-7$ or $5-4 x \geq 7, x \in R$ is
A
$\left(-\infty,-\frac{1}{2}\right) \cap[3, \infty)$
B
$\left(-\infty,-\frac{1}{2}\right) \cup(3, \infty)$
C
$\left(-\infty,-\frac{1}{2}\right] \cap(3, \infty)$
D
$\left(-\infty,-\frac{1}{2}\right] \cup[3, \infty)$
2
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { The solution set for the inequality } 13 x-5<15 x+4<7 x+12 ; x \in W \text { is } $$

A
$$\{0\}$$
B
$$\{0,1\}$$
C
$$\{\}$$
D
$$\{-4,-3,-2,-1,0\}$$
3
COMEDK 2024 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

The inequality $$4 x-3 \geq \frac{10 x-1}{3}$$ represents which of the following interval when $$x \in R$$

A
$$[-4, \infty)$$
B
$$[4, \infty)$$
C
$$(-\infty, 4]$$
D
$$\{4,5,6,7 \cdots\}$$
4
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { If } \frac{1}{2}\left(\frac{3 x}{5}+4\right) \geq \frac{1}{3}(x-6), x \in R \text { then } $$

A
$$ x \in(-\infty, 120) $$
B
$$ x \in(-\infty, 120] $$
C
$$ x \in(120, \infty) $$
D
$$ x \in[120, \infty) $$
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