The line $${{x - 2} \over 3} = {{y - 3} \over 4} = {{z - 4} \over 5}$$ is parallel to the plane

The equation of a plane passing through the line of intersection of the planes $$x+2y+3z=2,x-y+z=3$$ and at a distance $$\frac{2}{\sqrt3}$$ from the point $$(3,1,-1)$$ is

The angle between the lines $$2x=3y=-z$$ and $$6x=-y=-4z$$ is

The point of intersection of the lines $${{x - 1} \over 2} = {{y - 2} \over 3} = {{z - 3} \over 4}$$ and $${{x - 4} \over 5} = {{y - 1} \over 2} = z$$ is