The equation of normal to the curve $$y = {(1 + x)^y} + {\sin ^{ - 1}}({\sin ^2}x)$$ at $$x = 0$$ is

If $$y = {2^{\log x}}$$, then $${{dy} \over {dx}}$$ is

If $$y = {\cos ^2}{{3x} \over 2} - {\sin ^2}{{3x} \over 2}$$, then $${{{d^2}y} \over {d{x^2}}}$$ is

If $${x^x} = {y^y}$$, then $${{dy} \over {dx}}$$ is