Match the coordination compounds in Column I having the given type of hybridisation of $\mathrm{M}^{\mathrm{n}+}$ ion and magnetic moment as given in Column II.
| Coordination compounds | Hybridisation & Magnetic nature | ||
|---|---|---|---|
| A. | $\mathrm{Ni}(\mathrm{CO})_4$ | P. | $\mathrm{sp}^3, \quad \mu=5.92 \mathrm{BM}$ |
| B. | $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ | Q. | $\mathrm{sp}^3, \quad \mu=2.84 \mathrm{BM}$ |
| C. | $\left[\mathrm{Ni}(\mathrm{Cl})_4\right]^{2-}$ | R. | $\mathrm{sp}^3, \quad \mu=0$ |
| D. | $\left[\mathrm{MnBr}_4\right]^{2-}$ | S. | $\mathrm{dsp}^2, \quad \mu=0$ |
Which of the following 2 compounds exhibit both Geometrical and Structural isomerism?
$$\begin{aligned} & \mathrm{A}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{NO}_2 \\ & \mathrm{~B}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right) \mathrm{Br}\right] \mathrm{SO}_4 \\ & \mathrm{C}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3\left(\mathrm{NO}_2\right)_3\right] \\ & \mathrm{D}=\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 \end{aligned}$$
Based on Valence Bond Theory, match the complexes listed in Column I with the number of unpaired electrons on the central metal ion, given in Column II
| No. | Complex ions | No. | Number of unpaired electrons |
|---|---|---|---|
| (A) | $$ \left[\mathrm{Fe} \mathrm{F}_6\right]^{3-} $$ |
(P) | 0 |
| (B) | $$ \left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} $$ |
(P) | 1 |
| (C) | $$ \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} $$ |
(R) | 5 |
| (D) | $$ \left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-} $$ |
(S) | 4 |
Given below are 4 statements. Two of these are correct statements. Identify them.
A. $$\mathrm{Co}^{2+}$$ is easily oxidised to $$\mathrm{Co}^{3+}$$ in the presence of a strong ligand like $$\mathrm{CN}^{-}$$
B. $$[\mathrm{Fe}(\mathrm{CN})_6]^{4-}$$ is an octahedral complex ion which is paramagnetic in nature.
C. Removal of $$\mathrm{H}_2 \mathrm{O}$$ molecules from $$[\mathrm{Ti}(\mathrm{H}_2 \mathrm{O})_6] \mathrm{Cl}_3$$ on strong heating converts it to a colourless compound.
D. Crystal Field splitting in Octahedral and Tetrahedral complexes is given by the equation $$\Delta_0=4 / 9 \Delta_t$$