1
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

Based on Crystal Field theory, match the Complex ions listed in Column I with the electronic configuration in the d orbitals of the central metal ion listed in Column II.

No. Complexion No. d orbital configuration of central metal ion.
(A) $$
\left[M n(C N)_6\right]^{4-}
$$
(P) $$
e_g^2 t_{2 g}^3
$$
(B) $$
\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}
$$
(Q) $$
t_{2 g}^4 e_g^2
$$
(C) $$
\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}
$$
(R) $$
t_{2 g}^5
$$
(D) $$
\left[\mathrm{MnCl}_4\right]^{2-}
$$
(S) $$
t_{2 g}^5 e_g^2
$$

A
$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q} $$
B
$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P} $$
C
$$ \mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{R} $$
D
$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q} $$
2
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Which among the following is diamagnetic?

A
$$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$$
B
$$\left[\mathrm{Co}\left(\mathrm{F}_6\right)\right]^{3-}$$
C
$$\left[\mathrm{NiCl}_4\right]^{2-}$$
D
$$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$$
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The complex $$\left[\mathrm{PtCl}_2(\mathrm{en})_2\right]^{2+}$$ ion shows

A
structural isomerism
B
geometrical isomerism only
C
optical isomerism only
D
geometrical and optical isomerism
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The blue colouration obtained from the Lassaigne's test of nitrogen is due to the formation of

A
$$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$$
B
$$\mathrm{Fe}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]_5$$
C
$$\mathrm{K}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]_5$$
D
$$\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$$
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