1
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Choose the correct reason:

o-hydroxybenzaldehyde is a liquid at room temperature while $p$-hydroxy-benzaldehyde is a high melting solid, because

A

o-hydroxybenzaldehyde shows only weak Vanderwal's forces of attraction while in $p$ hydroxy benzaldehyde there is strong Vanderwal's forces of attraction in solid state

B

o-hydroxybenzaldehyde shows association of the molecules while in $p$-hydroxy benzaldehyde there is no association among the molecules

C

o-hydroxybenzaldehyde shows intramolecular hydrogen bonding while in $p$-hydroxy benzaldehyde there is no intramolecular hydrogen bonding

D

p-hydroxybenzaldehyde, shows intramolecular hydrogen bonding while in o-hydroxy benzaldehyde there is stronger intermolecular hydrogen bonding

2
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Which one of the following is the correct statement?

A

Acetone reacts with $\mathrm{NH}_2-\mathrm{NH}_2 / \mathrm{KOH}$ in Glycol on heating to form the saturated hydrocarbon, Butane

B

Acetone undergoes reaction in presence of $\mathrm{Ba}(\mathrm{OH})_2$ on heating to form 4-Methylpent-3-en-2-one

C

Acetophenone on reaction with $\mathrm{I}_2 / \mathrm{Na}_2 \mathrm{CO}_3(\mathrm{aq})$ does not undergo any reaction due to the presence of deactivating $-\mathrm{COCH}_3$ group

D

Acetophenone cannot be prepared on reacting Benzoyl chloride with Dimethyl cadmium in ether solvent

3
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { Match the reactions in List I with the final products formed as given in List II. } $$

$$
\text { List I }
$$
$$
\text { List II }
$$
W $$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_3 \frac{(\text { i }) \mathrm{CrO}_3+\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}}{(\text { ii }) \mathrm{H}_3 \mathrm{O}+\text { heat }} \rightarrow
$$
P $$
\mathrm{R}_2 \mathrm{CO}
$$
X $$
\mathrm{RCOOC}_2 \mathrm{H}_5 \frac{(\text { i) } D I B A L-H}{(\text { ii }) \mathrm{H}_2 \mathrm{O}} \rightarrow
$$
Q $$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{COCH}_3
$$
Y $$
R C N \frac{(i) R-\mathrm{Mg}-\mathrm{X} / \text { dry ether }}{(i i) \mathrm{H}_3 \mathrm{O}^{+}} \rightarrow
$$
R $$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}
$$
Z $$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{COCl}+\left(\mathrm{CH}_3\right)_2 \mathrm{Cd} \text { in dry ether → }
$$
S $$
\mathrm{RCHO}
$$
A

$$ W-Q \quad X-P \quad Y-S \quad Z-R $$

B

$$ W-R \quad X-P \quad Y-Q \quad Z-S $$

C

$$ W-R \quad X-S \quad Y-P \quad Z-Q $$

D

$$ W-S \quad X-R \quad Y-Q \quad Z-P $$

4
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { The product formed in the following reaction is: } $$

COMEDK 2026 Afternoon Shift Chemistry - Aldehyde and Ketone Question 1 English

A

COMEDK 2026 Afternoon Shift Chemistry - Aldehyde and Ketone Question 1 English Option 1

B

COMEDK 2026 Afternoon Shift Chemistry - Aldehyde and Ketone Question 1 English Option 2

C

COMEDK 2026 Afternoon Shift Chemistry - Aldehyde and Ketone Question 1 English Option 3

D

COMEDK 2026 Afternoon Shift Chemistry - Aldehyde and Ketone Question 1 English Option 4

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