1
COMEDK 2022
+1
-0

Calculate the molar conductance of 0.025 M aqueous solution of calcium chloride at 25$$^\circ$$C. The specific conductance of calcium chloride is 12.04 $$\times$$ 10$$^{-2}$$ Sm$$^{-1}$$

A
4.816 $$\times$$ 10$$^{-5}$$ Sm$$^2$$ mol$$^{-1}$$
B
3.816 $$\times$$ 10$$^{-5}$$ Sm$$^2$$ mol$$^{-1}$$
C
381.6 $$\times$$ 10$$^{-5}$$ Sm$$^2$$ mol$$^{-1}$$
D
481.6 $$\times$$ 10$$^{-5}$$ Sm$$^2$$ mol$$^{-1}$$
2
COMEDK 2021
+1
-0

Given that molar conductances for Ba(OH)$$_2$$, BaCl$$_2$$ and NH$$_4$$Cl are 523.28, 280.0 and 129.8 $$\Omega^{-1}$$ cm$$^2$$ mol$$^{-1}$$ respectively. What is the molar conductivity ($$\Omega^{-1}$$ cm$$^2$$ mol$$^{-1}$$) of NH$$_4$$OH?

A
502.88
B
251.44
C
1005.76
D
209.42
3
COMEDK 2021
+1
-0

The specific conductivity of a solution containing 1.0 g of anhydrous BaCl$$_2$$ in 200 cm$$^3$$ of the solution has been found to be 0.0058 Scm$$^{-1}$$. The molar and equivalent conductivity of the solution respectively are

A
120.83 S cm$$^2$$ eq$$^{-1}$$ and 241.67 S cm$$^2$$ eq$$^{-1}$$
B
150.5 S cm$$^2$$ eq$$^{-1}$$ and 289.7 S cm$$^2$$ eq$$^{-1}$$
C
241.6 S cm$$^2$$ mol$$^{-1}$$ and 120.83 S cm$$^2$$ eq$$^{-1}$$
D
248.6 S cm$$^2$$ mol$$^{-1}$$ and 180.3 S cm$$^2$$ eq$$^{-1}$$
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