COMEDK 2023 Evening Shift | Electrochemistry Question 3 | Chemistry

The Molar conductivity of $$0.05 \mathrm{M}$$ solution of $$\mathrm{MgCl}_2$$ is $$194.5 \mathrm{~ohm}^{-1} \mathrm{~cm}^2$$ per mole at room temperature. A Conductivity cell with electrodes having $$3.0 \mathrm{~cm}^2$$ surface area and $$1.0 \mathrm{~cm}$$ apart is filled with the solution of $$\mathrm{MgCl}_2$$. What would be the resistance offered by the conductivity cell?

114.25 ohms

0.00291 ohms

402.6 ohms

34.27 ohms

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

If electrolysis of water is carried out for a time duration of 2 hours, how much electric current in amperes would be required to liberate $$100 \mathrm{~ml}$$ of $$\mathrm{O}_2$$ gas measured under standard conditions of temperature and pressure?

0.1723 A

4.178 A

0.8616 A

0.2393 A

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

Match the items in Column I with their description in Column II

S.No.	Column I	S.No.	Column II
A	Kappa K	P	Intensive property.
B	$$\mathrm{E_{cell}^0}$$	Q	Extensive property.
C	Molar conductivity	R	Decreases with decrease in concentration of both strong and weak electrolytes.
D	$$\mathrm{\Delta G_{cell}}$$	S	Increases with dilution.

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{P} $$

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{Q} $$

$$ \mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{R} $$

$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P} $$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

When Lead Storage battery is in the process of getting charged which one of the following reactions takes place?

$$\mathrm{PbO}_{2(s)}$$ is reduced.

$$\mathrm{PbSO}_{4(\mathrm{~s})}$$ gets converted to $$\mathrm{Pb}_{(\mathrm{S})}$$ and $$\mathrm{PbO}_{2(\mathrm{~s})}$$

$$\mathrm{SO}_3$$ gas gets liberated and $$\mathrm{PbO}_{2(\mathrm{~s})}$$ is formed.

$$\mathrm{Pb}_{(\mathrm{S})}$$ gets consumed.

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