MHT CET 2023 11th May Evening Shift | Electrochemistry Question 19 | Chemistry

Calculate the $$\mathrm{E}_{\text {cell }}^{\circ}$$ for $$\mathrm{Zn}_{(\mathrm{s})}\left|\mathrm{Zn}_{(\mathrm{IM})}^{++}\right|\left|\mathrm{Cd}_{(\mathrm{IM})}^{++}\right| \mathrm{Cd}_{(\mathrm{s})}$$ at $$25^{\circ} \mathrm{C}\left[\mathrm{E}_{\mathrm{Zn}}^0=-0.763 \mathrm{~V} ; \mathrm{E}_{\mathrm{Cd}}^{\circ}=-0.403 \mathrm{~V}\right]$$

$$0.36 \mathrm{~V}$$

$$1.17 \mathrm{~V}$$

$$-0.36 \mathrm{~V}$$

$$-1.17 \mathrm{~V}$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

Find the number of faradays of electricity required to produce $$45 \mathrm{~g}$$ of $$\mathrm{Al}$$ from molten $$\mathrm{Al}_2 \mathrm{O}_3$$.

(At. mass of $$\mathrm{Al}=27$$ )

1 F

3 F

5 F

7 F

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

The molar conductivity of $$0.02 \mathrm{~M} \mathrm{~AgI}$$ at $$298 \mathrm{~K}$$ is $$142.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$. What is its conductivity?

$$1.42 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$2.41 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$2.85 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$7.11 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

Which among the following is CORRECT formula for determination of cell constant?

$$\frac{l}{\mathrm{a}}=\frac{\mathrm{k}}{\mathrm{R}}$$

$$\frac{l}{\mathrm{a}}=\mathrm{k} \cdot \mathrm{R}$$

$$\frac{l}{\mathrm{a}}=\frac{\mathrm{R}}{\mathrm{k}}$$

$$\frac{l}{\mathrm{a}}=\frac{1}{\mathrm{R}}$$

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