MHT CET 2023 12th May Evening Shift | Electrochemistry Question 13 | Chemistry

Calculate the $$\mathrm{E}_{\text {cell }}$$ for $$\mathrm{Zn}_{(\mathrm{s})}\left|\mathrm{Zn}_{(0.1 \mathrm{M})}^{++}\right|\left|\mathrm{Cr}_{(0.1 \mathrm{M})}^{+++}\right| \mathrm{Cr}_{(\mathrm{s})}$$ at $$25^{\circ} \mathrm{C}$$ if $$\mathrm{E}_{\text {cell }}^{\circ}$$ is $$0.02 \mathrm{~V}$$

$$-0.05 \mathrm{~V}$$

$$0.03 \mathrm{~V}$$

$$-0.06 \mathrm{~V}$$

$$0.07 \mathrm{~V}$$

MHT CET 2023 12th May Evening Shift

MCQ (Single Correct Answer)

-0

A conductivity cell containing $$5 \times 10^{-4} \mathrm{~M} \mathrm{~NaCl}$$ solution develops resistance $$14000 \mathrm{~ohms}$$ at $$25^{\circ} \mathrm{C}$$. Calculate the conductivity of solution if the cell constant is $$0.84 \mathrm{~cm}^{-1}$$

$$6.0 \times 10^{-5} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$3.0 \times 10^{-5} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$9.0 \times 10^{-5} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$12.0 \times 10^{-5} \Omega^{-1} \mathrm{~cm}^{-1}$$

MHT CET 2023 12th May Morning Shift

MCQ (Single Correct Answer)

-0

Calculate $$\Delta \mathrm{G}^{\circ}$$ for the reaction $$\mathrm{Mg}_{(\mathrm{s})}+\mathrm{Sn}_{(\mathrm{aq})}^{++} \longrightarrow \mathrm{Mg}_{(\mathrm{aq})}^{++}+\mathrm{Sn}_{(\mathrm{s})}$$ if $$\mathrm{E}_{\text {cell }}^0$$ is $$2.23 \mathrm{~V}$$.

$$-430.4 \mathrm{~kJ}$$

$$215.2 \mathrm{~kJ}$$

$$645.6 \mathrm{~kJ}$$

$$-860.8 \mathrm{~kJ}$$

MHT CET 2023 12th May Morning Shift

MCQ (Single Correct Answer)

-0

Electrolytic cells containing $$\mathrm{Zn}$$ and $$\mathrm{Al}$$ salt solutions are connected in series. If $$6.5 \mathrm{~g}$$ of $$\mathrm{Zn}$$ is deposited in one cell calculate mass of $$\mathrm{Al}$$ deposited in second cell (molar mass : $$\mathrm{Zn}=65, \mathrm{Al}=27$$ ) by passing definite quantity of electricity?

2.4 g

2.1 g

2.7 g

1.8 g

PREVIOUS NEXT

MHT CET Subjects