MHT CET 2023 10th May Evening Shift | Electrochemistry Question 24 | Chemistry

Calculate $$E_{\text {cell }}^{\circ}$$ in which following reaction occurs. $$\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{Ag}_{(\mathrm{IM})}^{+} \rightarrow \mathrm{Mg}_{(1 \mathrm{M})}^{+}+2 \mathrm{Ag}_{(\mathrm{s})}$$ if $$\mathrm{E}_{\mathrm{Ag}}^{\circ}=0.8 \mathrm{~V}$$ and $$\mathrm{E}_{\mathrm{Mg}}^{\circ}=-2.37 \mathrm{~V}$$

$$-3.17 \mathrm{~V}$$

$$3.17 \mathrm{~V}$$

$$-1.57 \mathrm{~V}$$

$$1.57 \mathrm{~V}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the conductivity of $$0.02 \mathrm{~M}$$ electrolyte solution if its molar conductivity $$407.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$ ?

$$8.144 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$4.072 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$7.15 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$6.055 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

Conductivity of a solution is $$1.26 \times 10^{-2} \Omega^{-1} \mathrm{~cm}^{-1}$$ Calculate molar conductivity for $$0.01 \mathrm{~M}$$ solution.

$$1.26 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$2.52 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$4.82 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$6.30 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following is NOT a difficulty in setting SHE?

To obtain pure hydrogen gas

To obtain dry hydrogen gas

To maintain exactly $$1 \mathrm{~atm}$$ pressure

To bring the reaction in reverse direction

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