1
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the foci of the ellipse $\frac{x^2}{16}+\frac{y^2}{b^2}=1$ and the foci of the hyperbola $\frac{x^2}{144}-\frac{y^2}{81}=\frac{1}{25}$ coincide, then the value of $b^2$ is
A
5
B
9
C
1
D
7
2
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
The length of the latus rectum of a conic $49 y^2-16 x^2=784$ is
A
$\frac{49}{2}$
B
$\frac{49}{\sqrt{2}}$
C
$\frac{7}{\sqrt{2}}$
D
$\frac{7}{2}$
3
COMEDK 2024 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

If the distance between the foci and the distance between the two directrixes are in the ratio $$3: 2$$ for a hyperbola $$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$$, then a : b is

A
$$1: 2$$
B
$$\sqrt{3}: \sqrt{2}$$
C
$$2: 1$$
D
$$\sqrt{2}: 1$$
4
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The distance between the foci of a hyperbola is 16 and its eccentricity is $$\sqrt{2}$$. Then its equation is

A
$$ x^2-y^2=32 $$
B
$$ 3 x^2-2 y^2=7 $$
C
$$ 2 x^2-3 y^2=7 $$
D
$$ \frac{x^2}{4}-\frac{y^2}{9}=1 $$
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