MHT CET 2026 18th April Morning Shift | Thermodynamics Question 17 | Chemistry

For a certain reaction, $\Delta\text{H}^\circ = 40\ \text{kJ}$ and $\Delta\text{S}^\circ = 80\ \text{JK}^{-1}$. Find the temperature so that $\Delta\text{G}^\circ = 0$

$500\ \text{K}$

$400\ \text{K}$

$300\ \text{K}$

$600\ \text{K}$

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

Which from following is correct expression of first law of thermodynamics for isothermal process?

$\text{W} = -\text{Q}$

$-\Delta\text{U} = -\text{W}$

$\Delta\text{U} = \text{Q}_\text{v}$

$\text{Q}_\text{p} = \Delta\text{U} + \text{P}_{\text{ext}}\Delta\text{V}$

MHT CET 2026 17th April Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the quantity of heat released from system when 2 moles of and ideal gas compressed isothermally from volume $25 \text{ dm}^3$ to $10 \text{ dm}^3$ at constant external pressure 4 bar.

$5 \cdot 5 \text{ kJ}$

$5 \cdot 0 \text{ kJ}$

$6 \cdot 5 \text{ kJ}$

$6 \cdot 0 \text{ kJ}$

MHT CET 2026 17th April Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the standard enthalpy of combustion of carbon monoxide if
$\Delta_f H^\circ (\text{CO}) = -110 \text{ kJ mol}^{-1}$
$\Delta_f H^\circ (\text{CO}_2) = -393 \text{ kJ mol}^{-1}$

$-503 \text{ kJ mol}^{-1}$

$-110 \text{ kJ mol}^{-1}$

$-283 \text{ kJ mol}^{-1}$

$-383 \text{ kJ mol}^{-1}$

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