4f⁵ 5d⁴ 6s¹

4f⁷ 5d¹ 6s²

4f³ 5d⁵ 6s²

4f⁴ 5d⁵ 6s¹

$${{1.196 \times {{10}^8}} \over \lambda }$$

$${{2.859 \times {{10}^5}} \over \lambda }$$

$${{2.859 \times {{10}^{16}}} \over \lambda }$$

$${{1.196 \times {{10}^{16}}} \over \lambda }$$

4

2

10

6

Equation can be used to calculate the change in energy when the electron changes orbit.

For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.

The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.

Larger the value of n, the larger is the orbit radius.