1
MCQ (Single Correct Answer)

NEET 2017

Predict the correct intermediate and product in the following reaction :

$${H_3}C - C \equiv CH\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{HgS{O_4}}^{{H_2}O,{H_2}S{O_4}}} \mathop {Intermediate}\limits_{(A)} \to \mathop {\Pr oduct}\limits_{(B)} $$
A
B
C
D

Explanation

2
MCQ (Single Correct Answer)

NEET 2017

Which one is the correct order of acidity?
A
CH$$ \equiv $$CH > CH3 $$-$$C$$ \equiv $$CH
                    > CH2 $$=$$ CH2 > CH3$$-$$CH3
B
CH $$ \equiv $$ CH > CH2 $$=$$ CH2
                    > CH3$$-$$C $$ \equiv $$ CH > CH3 $$-$$CH3
C
CH3$$-$$CH3 > CH2 $$=$$ CH2
                    > CH3 $$-$$C $$ \equiv $$ CH > CH$$ \equiv $$CH
D
CH2$$=$$CH2 > CH3 $$-$$ CH $$=$$ CH2
                    > CH3 $$-$$ C$$ \equiv $$ CH > CH $$ \equiv $$ CH

Explanation

Greater the character of C-atom in hydrocarbons, greater the electronegativity of that carbon and thus greater the acidic nature of the H attached to electronegative carbon.

Thus CH$$ \equiv $$CH > CH3 $$-$$C$$ \equiv $$CH
                    > CH2 $$=$$ CH2 > CH3$$-$$CH3
3
MCQ (Single Correct Answer)

NEET 2016 Phase 1

In the reaction


X and Y are
A
X = 2-Butyne,  Y = 2-Hexyne
B
X = 1-Butyne,  Y = 2-Hexyne
C
X = 1-Butyne,  Y = 3-Hexyne
D
X = 2-Butyne,  Y = 3-Hexyne

Explanation

4
MCQ (Single Correct Answer)

NEET 2016 Phase 1

The pair of electrons in the given carbanion, CH3C $$ \equiv $$ C$$-$$, is present in which of the following orbitals?
A
sp2
B
sp
C
2p
D
sp3

Explanation


Thus, pair of electrons is present in sp-hybridised orbital.

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