1
MCQ (Single Correct Answer)

AIPMT 2008

Percentage of free space in a body centred cubic unit cell is
A
34%
B
28%
C
30%
D
32%

Explanation

The ratio of volumes occupied by atoms in unit cell to the total volume of the unit cell is called as packing fraction or density of packing. For body centred cubic structure, packing fraction = 0.68 i.e., 68% of the unit cell is occupied by atoms and 32% is empty.
2
MCQ (Single Correct Answer)

AIPMT 2008

Which of the following statements is not correct?
A
The number of carbon atoms in a unit cell of diamond is 4
B
The number of Bravais lattices in which a crystal can be categorized is 14
C
The fraction of the total volume occupied by the atoms in a primitive cell is 0.48.
D
Molecular solids are generally volatile.

Explanation

Packing fraction for a cubic unit cell is given by

f = $${{Z \times {4 \over 3}\pi {r^3}} \over {{a^3}}}$$

where a = edge length, r = radius of cation and anion.

Efficiency of packing in simple cubic or primitive cell = π/6 = 0.52 or 52 %

It means 52 % of unit cell is occupied by atoms and 48 % is empty.
3
MCQ (Single Correct Answer)

AIPMT 2008

If $$a$$ stands for the edge length of the cubic systems: simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these systems will be respectively
A
$${1 \over 2}a:{{\sqrt 3 } \over 2}a:{{\sqrt 2 } \over 2}a$$
B
$$1a:\sqrt 3 a:\sqrt 2 a$$
C
$${1 \over 2}a:{{\sqrt 3 } \over 4}a:{1 \over {2\sqrt 2 }}a$$
D
$${1 \over 2}a:\sqrt 3 a:{1 \over {\sqrt 2 }}a$$

Explanation

For Simple cubic : r+ + r = $${a \over 2}$$

For Body centred : r+ + r = $${{a\sqrt 2 } \over 4}$$

For Face centered: r+ + r = $${a \over {2\sqrt 2 }}$$

$$ \therefore $$ Ratio of radii of the three will be

= $${1 \over 2}a:{{\sqrt 3 } \over 4}a:{1 \over {2\sqrt 2 }}a$$
4
MCQ (Single Correct Answer)

AIPMT 2008

With which one of the following elements silicon should be doped so as to give p-type of semiconductor?
A
Selenium
B
Boron
C
Germanium
D
Arsenic

Explanation

The semiconductors formed by the introduction of impurity atoms containing one elecron less than the parent atoms of insulators are termed as p-type semiconductors. Therefore silicon containing 14 electrons has to be doped with boron containing 13 electrons to give a p-type semi-conductor.

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