1
MCQ (Single Correct Answer)

AIPMT 2011 Prelims

If n = 6, the correct sequence for filling of electrons will be
A
$$ns \to \left( {n - 2} \right)f \to \left( {n - 1} \right)d \to np$$
B
$$ns \to \left( {n - 1} \right)d \to \left( {n - 2} \right)f \to np$$
C
$$ns \to \left( {n - 2} \right)f \to np \to \left( {n - 1} \right)d$$
D
$$ns \to np\left( {n - 1} \right)d \to \left( {n - 2} \right)f$$
2
MCQ (Single Correct Answer)

AIPMT 2011 Prelims

The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e., $$\lambda $$1 and $$\lambda $$2 will be
A
$$\lambda $$1 = $$\lambda $$2
B
$$\lambda $$1 = 2$$\lambda $$2
C
$$\lambda $$1 = 4$$\lambda $$2
D
$$\lambda $$1 = $${1 \over 2}$$ $$\lambda $$2

Explanation

E1 = $${{hc} \over {{\lambda _1}}}$$ and E2 = $${{hc} \over {{\lambda _2}}}$$

$${{{E_1}} \over {{E_2}}}$$ = $${{hc} \over {{\lambda _1}}} \times {{{\lambda _2}} \over {hc}}$$ = $${{{\lambda _2}} \over {{\lambda _1}}}$$

$$ \Rightarrow $$ $$25 \over 50$$ = $${{{\lambda _2}} \over {{\lambda _1}}}$$

$$ \Rightarrow $$ $$1 \over 2$$ = $${{{\lambda _2}} \over {{\lambda _1}}}$$ $$ \Rightarrow $$ $$\lambda _1$$ = 2$$\lambda _2$$
3
MCQ (Single Correct Answer)

AIPMT 2011 Prelims

The total number of atomic orbitals in fourth energy level of an atom is
A
8
B
16
C
32
D
4

Explanation

The total number of atomic orbitals in any energy level is n2.

$$ \therefore $$ 42 = 16
4
MCQ (Single Correct Answer)

AIPMT 2010 Mains

A 0.66 kg ball is moving with a speed of 100 m/s. The associated wavelength will be

(h = 6.6 $$ \times $$ 10$$-$$34 J s)
A
6.6 $$ \times $$ 10$$-$$32 m
B
6.6 $$ \times $$ 10$$-$$34 m
C
1.0 $$ \times $$ 10$$-$$35 m
D
1.0 $$ \times $$ 10$$-$$32 m

Explanation

According to the de-Broglie equation, $$\lambda $$ = $${h \over {mv}}$$

$$ \therefore $$ $$\lambda $$ = $${{6.6 \times {{10}^{ - 34}}} \over {0.66 \times 100}} = 1 \times {10^{ - 35}}\,m$$

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