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1

AIPMT 2007

MCQ (Single Correct Answer)
Identify the correct order of the size of the following :
A
Ca2+ < K+ < Ar < Cl$$-$$ < S2$$-$$
B
Ar < Ca2+ < K+ < Cl$$-$$ < S2$$-$$
C
Ca2+ < Ar < K+ < Cl$$-$$ < S2$$-$$
D
Ca2+ < K+ < Ar < S2$$-$$ < Cl$$-$$

Explanation

Among isoelectronic ions, ionic radius of anions is more than that of cations. Further size of the anion increases with increase in negative charge and size of the cation decreases with increase in positive charge.
2

AIPMT 2006

MCQ (Single Correct Answer)
Which one of the following orders is not in accordance with the property stated against it ?
A
F2 > Cl2 > Br2 > I2 : Bond dissociation energy
B
F2 > Cl2 > Br2 > I2 : Oxidising power
C
HI > HBr > HCl > HF : Acidic property in water
D
F2 > Cl2 > Br2 > I2 : Electronegativity

Explanation

$$\mathop {F - F}\limits_{38} \,\,\,\mathop {Cl - Cl}\limits_{57} \,\,\mathop {Br - Br}\limits_{45.5} \,\,\mathop {I - I}\limits_{35.6} $$
X - X bond dissociation energy (kcal/mol)

The lower value of bond dissociation energy of fluorine is due to the high inter-electronic repulsion between non-bonding electrons in the 2p-orbitals of fluorine. As a result F - F bond is weaker in comparison to Cl - Cl and Br - Br bonds.
3

AIPMT 2005

MCQ (Single Correct Answer)
Which one of the following arrangements represents the correct order of electron gain enthalpy (with negative sign) of the given atomic species ?
A
S < O < Cl < F
B
Cl < F < S < O
C
F < Cl < O < S
D
O < S < F < Cl

Explanation

The molar enthalpy change accompanying the addition of an electron to an atom (or ion) is known as electron gain enthalpy.
Generally in increases on moving from left to right in a period and in a group it decreases as the size increases.
Exception: Because of the small size of F, electron-electron repulsion present in its relatively compact 2p-subshell, do not easily allow the addition of an extra electron. On the other hand, Cl because of its comparatively bigger size than F, allows the addition of an extra electron more easily.
$$\mathop O\limits_{ - 1.48} < \mathop S\limits_{ - 2.0} < \mathop F\limits_{ - 3.6} < \mathop {Cl}\limits_{ - 3.8} $$
4

AIPMT 2004

MCQ (Single Correct Answer)
Ionic radii are
A
inversely proportional to effective nuclear charge
B
inversely proportional to square of effective nuclear charge
C
directly proportional to effective nuclear charge
D
directly proportional to square of effective nuclear charge.

Explanation

Ionic radius in the nth orbit is given by

rn = $${{{n^2}{a_0}} \over {{Z^*}}}$$ or, $${r_n} \propto {1 \over {{Z^*}}}$$

When n is the principal quantum number, a0 the Bohr's radius of H-atom and Z*, the effective nuclear charge.

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