Homolytic fission of the following alkanes forms free radicals CH3 $$-$$ CH3 , CH3 $$-$$ CH2 $$-$$ CH3 , (CH3 )2 CH $$-$$ CH3 , CH3 $$-$$ CH2 $$-$$CH(CH3 )2 .
A
$$\eqalign{
& {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - \,C{H_2}C{H_3}\, < C{H_3}\, - \,\mathop C\limits^ \bullet H - \,C{H_3} \cr
& < C{H_3}\, - \,\mathop C\limits^ \bullet {H_2}\, < {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \cr} $$
B
$$\eqalign{
& C{H_3}\, - \,\mathop C\limits^ \bullet {H_2}\, < \,C{H_3}\, - \,\mathop C\limits^ \bullet HH\, - \,C{H_3}\, < \cr
& {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - \,C{H_2}\, - \,C{H_3}\, < \,{\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \cr} $$
C
$$\eqalign{
& C{H_3} - \mathop C\limits^ \bullet {H_2} < C{H_3} - \mathop C\limits^ \bullet H - C{H_3} < \cr
& {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \, < {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - C{H_2}C{H_3} \cr} $$
D
$$\eqalign{
& {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \, < {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - C{H_2}C{H_3} < \cr
& C{H_3} - \mathop C\limits^ \bullet H - C{H_3} < C{H_3} - \mathop C\limits^ \bullet {H_2} \cr} $$
CHECK ANSWER
Explanation Stability depends on number of
hyperconjugative structure. More the number of hyperconjugative structure, the greater is the stability.
