MHT CET 2025 26th April Evening Shift | Hydrocarbons Question 3 | Chemistry

$$ \begin{aligned} \mathrm{C}_6 \mathrm{H}_5 \mathrm{Br}+\mathrm{CH}_3-\mathrm{Br}+2 \mathrm{Na} \xrightarrow[\text { ether }]{\text { dry }} \mathrm{C}_6 \mathrm{H}_5-\mathrm{CH}_3+2 \mathrm{NaBr} \end{aligned} $$

$$ \begin{aligned} 2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{Br}+2 \mathrm{Na} \xrightarrow[\text { ether }]{\text { dr }} & \mathrm{C}_2 \mathrm{H}_5-\mathrm{C}_2 \mathrm{H}_5+2 \mathrm{NaBr} \end{aligned} $$

$$ 2 \mathrm{CH}_3 \mathrm{Br}+2 \mathrm{Na} \xrightarrow[\text { ether }]{\text { dry }} $$$$ \,\,\mathrm{CH}_3-\mathrm{CH}_3+2 \mathrm{NaBr} $$

$$ \begin{aligned} 2 \mathrm{C}_6 \mathrm{H}_5 \mathrm{Br}+2 \mathrm{Na} \xrightarrow[\text { ether }]{\text { dry }} & \mathrm{C}_6 \mathrm{H}_5-\mathrm{C}_6 \mathrm{H}_5+2 \mathrm{NaBr} \end{aligned} $$

MHT CET 2025 26th April Evening Shift

MCQ (Single Correct Answer)

-0

Identify the product formed in the following reaction.

$$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{MgBr} \xrightarrow[\text { ii) dil. HCl }]{\text { i) Dry ice/ dry ether }} \text { Product } $$

Ethanoic acid

Propanoic acid

2-Methylpropanoic acid

Butanoic acid

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following reagents is used to convert $\mathrm{C} \equiv \mathrm{C}$ triple bond to $\mathrm{C}=\mathrm{C}$ double bond to give Cis isomer of alkene?

$\mathrm{ZnCl}_2 / \mathrm{HCl}$

Pd -C/quinoline

Na / liquid $\mathrm{NH}_3$

$\mathrm{Na} / \mathrm{Hg}$ in $\mathrm{H}_2 \mathrm{O}$

MHT CET 2025 26th April Morning Shift

MCQ (Single Correct Answer)

-0

What is the difference in molar mass of Undecane and Dodecane?

$10 \mathrm{~g} \mathrm{~mol}^{-1}$

$20 \mathrm{~g} \mathrm{~mol}^{-1}$

$140 \mathrm{~g} \mathrm{~mol}^{-1}$

$14 \mathrm{~g} \mathrm{~mol}^{-1}$

PREVIOUS NEXT

MHT CET Subjects