1
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The points on the $$x$$-axis whose perpendicular distance from the line $$\frac{x}{3}+\frac{y}{4}=1$$ is 4 units are

A
$$(8,0)$$ and $$(-2,0)$$
B
$$(-8,0)$$ and $$(-2,0)$$
C
$$(8,0)$$ and $$(2,0)$$
D
$$(-8,0)$$ and $$(2,0)$$
2
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Find the direction in which a straight line must be drawn through the point $$(1,2)$$ so that its point of intersection with the line $$x+y=4$$ may be at a distance of $$\sqrt{\frac{2}{3}}$$ from this point.

A
$$ 60^{\circ} \text { or } 120^{\circ} $$
B
$$ 50^{\circ} \text { or } 100^{\circ} $$
C
$$ 15^{\circ} \text { or } 75^{\circ} $$
D
$$ 30^{\circ} \text { or } 150^{\circ} $$
3
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The perpendicular distance of a line from the origin is 5 units and its slope is $$-1$$. The equation of the line is

A
$$x+y \pm 5 \sqrt{2}=0$$
B
$$x-y \pm 2 \sqrt{5}=0$$
C
$$x+y \pm 2 \sqrt{5}=0$$
D
$$x-y \pm 5 \sqrt{2}=0$$
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let the equation of pair of lines $$y=m_1 x$$ and $$y=m_2 x$$ can be written as $$\left(y-m_1 x\right)\left(y-m_2 x\right)=0$$. Then, the equation of the pair of the angle bisector of the line $$3 y^2-5 x y-2 x^2=0$$ is

A
$$x^2+5 x y-y^2=0$$
B
$$x^2-5 x y+y^2=0$$
C
$$x^2-x y+y^2=0$$
D
$$x^2+x y-y^2=0$$
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