1
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

The $\Delta \mathrm{G}^{\circ}$ for the reaction, $C d^{2+}(a q)+Z n(s) \rightarrow Z n^{2+}(a q)+C d(s)$ is:

$\left[E_{C d^{2+} / C d}^o=-0.403, E_{Z n^{2+} / Z n}^o=-0.763 \mathrm{~V}\right]$

A

$-69.5 k J$

B

$-72.2 kJ$

C

$-44.5 kJ$

D

$-50 kJ$

2
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

$$ \begin{aligned} &\text { Using the data given below, the strongest reducing agent is: }\\ &\begin{array}{ll} \mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7}^{\mathrm{o}}{ }^{2-} / \mathrm{Cr}^{3+}=1.33 \mathrm{~V} & \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^{\mathrm{o}}=1.51 \mathrm{~V} \\ \mathrm{E}_{\mathrm{Cl}_2 / \mathrm{Cl}^{-}}^{\mathrm{O}}=1.36 \mathrm{~V} & \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\mathrm{O}}=-0.74 \mathrm{~V} \end{array} \end{aligned} $$

A

$ Cr$

B

$\mathrm{Mn}^{2+}$

C

$\mathrm{Cr}^{3+}$

D

$\mathrm{Cl}^{-}$

3
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider a Galvanic cell in which the following reactions occurs: $\mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{s})$. What is the standard potential of the cell? Given: $\mathrm{E}^0\left(\mathrm{Ag}^{+} / \mathrm{Ag}\right)=\mathrm{aV} \quad \mathrm{E}^0\left(\mathrm{Fe}^{2+} / \mathrm{Fe}\right)=\mathrm{bV} \quad \& \quad \mathrm{E}^0\left(\mathrm{Fe}^{3+} / \mathrm{Fe}\right)=\mathrm{cV}$

A

$(a+2 b-3 c) V$

B

$(a+b+2 c) V$

C

$(a-2 c+b) V$

D

$(a+c-2 b) V$

4
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Identify the correct mathematical expression which represents the variation in molar conductivity of a weak acid having concentration C and ionisation constant $\mathrm{K}_{\mathrm{a}}$

( $\lambda_m^{\infty}=$ molar conductivity at infinite dilution, $\lambda_{\mathrm{m}}=$ molar conductivity at concentration C )

A

$K_a=\lambda_m^2 C / \lambda_m^{\infty}\left(\lambda_m^{\infty}-\lambda_m\right)$

B

$K_a=\lambda_m \lambda_m^{\infty}-\left(\lambda_m^{\infty}\right)^2+\lambda_m^2 C$

C

$\lambda_m+\lambda_m^{\infty}+K_a C^{\frac{1}{2}}=0$

D

$K_a=\lambda_m^2 C / \lambda_m^{\infty}\left(\lambda_m^{\infty}+\lambda_m\right)$

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