COMEDK 2024 Morning Shift | Chemical Kinetics Question 8 | Chemistry

For the reaction $$\mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{NO}_{(\mathrm{g})} \rightarrow 2 \mathrm{NOCl}_{(\mathrm{g})}$$, the following data was obtained:

Experiment No.	Initial concentration of $$\mathrm{Cl_2}$$ ($$\mathrm{M}$$)	Initial concentration of $$\mathrm{NO}$$ ($$\mathrm{M}$$)	Initial reaction rate ($$\mathrm{M}$$/min)
I	0.15	0.15	0.60
II	0.30	0.15	1.20
III	0.15	0.3	2.40
IV	0.25	0.25	2.78

Identify the order of the reaction with respect to $$\mathrm{Cl}_2, \mathrm{NO}$$ and the value of Rate constant.

$$ \text { Order with respect to } \mathrm{Cl}_2=2 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=355.5 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1} $$

$$ \text { Order with respect to } \mathrm{Cl}_2=0 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=8.0 \mathrm{~min}^{-1} $$

$$ \text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=2 \quad \mathrm{k}=177.7 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1} $$

$$ \text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=26.66 \mathrm{~mol}^{-1} \mathrm{Lmin}^{-1} $$

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

Given below are 4 graphs [A], [B], [C] and [D]

COMEDK 2024 Morning Shift Chemistry - Chemical Kinetics Question 6 English

Identify the 2 graphs that represent a Zero order reaction?

[A] and [D]

[A] and [B]

[B] and [C]

[C] and [D]

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

A given chemical reaction is represented by the following stoichiometric equation.

$$3 X+2 Y+\frac{5}{2} Z \rightarrow P_1+P_2+P_3$$

The rate of reaction can be expressed as _________.

$$\frac{2}{3}\left(\frac{d[X]}{d t}\right)=\left(\frac{d[Y]}{d t}\right)=\frac{4}{5}\left(\frac{d[Z]}{d t}\right)$$

$$\frac{3}{2}\left(\frac{d[X]}{d t}\right)=\frac{1}{4}\left(\frac{d[Y]}{d t}\right)=\frac{8}{5}\left(\frac{d[Z]}{d t}\right)$$

$$\frac{4}{15}\left(\frac{d[X]}{d t}\right)=\frac{4}{5}\left(\frac{d[Y]}{d t}\right)=\frac{8}{15}\left(\frac{d[Z]}{d t}\right)$$

$$\left(\frac{d[X]}{d t}\right)=\frac{3}{2}\left(\frac{d[Y]}{d t}\right)=\frac{15}{4}\left(\frac{d[Z]}{d t}\right)$$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

How much faster would a reaction proceed at $$25^{\circ} \mathrm{C}$$ than at $$0^{\circ} \mathrm{C}$$ if the activation energy is $$65 \mathrm{~kJ}$$?

4 times

6 times

12 times

11 times

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