COMEDK 2025 Morning Shift | Coordination Compounds Question 10 | Chemistry

A	B	C	D
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2$	$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right]$	$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}$	$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3$

$\mathrm{B}>\mathrm{C}>\mathrm{A}>\mathrm{D}$

$\mathrm{D}>\mathrm{A}>\mathrm{C}>\mathrm{B}$

$\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}$

$\mathrm{A}>\mathrm{B}>\mathrm{D}>\mathrm{C}$

COMEDK 2025 Morning Shift

MCQ (Single Correct Answer)

-0

Match the coordination compounds in Column I having the given type of hybridisation of $\mathrm{M}^{\mathrm{n}+}$ ion and magnetic moment as given in Column II.

	Coordination compounds		Hybridisation & Magnetic nature
A.	$\mathrm{Ni}(\mathrm{CO})_4$	P.	$\mathrm{sp}^3, \quad \mu=5.92 \mathrm{BM}$
B.	$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$	Q.	$\mathrm{sp}^3, \quad \mu=2.84 \mathrm{BM}$
C.	$\left[\mathrm{Ni}(\mathrm{Cl})_4\right]^{2-}$	R.	$\mathrm{sp}^3, \quad \mu=0$
D.	$\left[\mathrm{MnBr}_4\right]^{2-}$	S.	$\mathrm{dsp}^2, \quad \mu=0$

$\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}$

$A=S \quad B=R \quad C=P \quad D=Q$

$\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{R} \quad \mathrm{D}=\mathrm{Q}$

$\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{R}$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Which of the following 2 compounds exhibit both Geometrical and Structural isomerism?

$$\begin{aligned} & \mathrm{A}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{NO}_2 \\ & \mathrm{~B}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right) \mathrm{Br}\right] \mathrm{SO}_4 \\ & \mathrm{C}=\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3\left(\mathrm{NO}_2\right)_3\right] \\ & \mathrm{D}=\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 \end{aligned}$$

A & C

C & B

B & D

A & B

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Based on Valence Bond Theory, match the complexes listed in Column I with the number of unpaired electrons on the central metal ion, given in Column II

No.	Complex ions	No.	Number of unpaired electrons
(A)	$$ \left[\mathrm{Fe} \mathrm{F}_6\right]^{3-} $$	(P)	0
(B)	$$ \left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} $$	(P)	1
(C)	$$ \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} $$	(R)	5
(D)	$$ \left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-} $$	(S)	4

$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{R} \quad \mathrm{D}=\mathrm{P} $$

$$ \mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{R} $$

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{Q} $$

$$ \mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P} $$

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