1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A random variable X with probability distribution is given below

$$
\mathrm{X}=x_i
$$
2 3 4 5
$$
\mathrm{P}\left(\mathrm{X}=x_i\right)
$$
$$
\frac{5}{k}
$$
$$
\frac{7}{k}
$$
$$
\frac{9}{k}
$$
$$
\frac{11}{k}
$$

The mean of this distribution is

A
$$ \frac{61}{16} $$
B
$$ \frac{61}{8} $$
C
7
D
$$ \frac{61}{4} $$
2
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A number $$\mathrm{n}$$ is chosen at random from $$s=\{1,2,3, \ldots, 50\}$$. Let $$\mathrm{A}=\{n \in s: n$$ is a square $$\}$$, $$\mathrm{B}=\{n \in s: n$$ is a prime$$\}$$ and $$\mathrm{C}=\{n \in s: n$$ is a square$$\}$$. Then, correct order of their probabilities is

A
$$p(A) < p(B) < p(C)$$
B
$$p(A) > p(B) > p(C)$$
C
$$p(\mathrm{~B}) < p(\mathrm{~A}) < p(C)$$
D
$$p(A) > p(c) > p(B)$$
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A five-digits number is formed by using the digits $$1,2,3,4,5$$ with no repetition. The probability that the numbers 1 and 5 are always together, is

A
$$\frac{2}{5}$$
B
$$\frac{1}{5}$$
C
$$\frac{3}{5}$$
D
$$\frac{1}{4}$$
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If a number $n$ is chosen at random from the set $$\{11,12,13, \ldots \ldots, 30\}$$. Then, the probability that $$n$$ is neither divisible by 3 nor divisible by 5, is

A
$$\frac{7}{20}$$
B
$$\frac{9}{20}$$
C
$$\frac{11}{20}$$
D
$$\frac{13}{20}$$
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