1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { If } \sin A=\frac{4}{5} \text { and } \cos B=\frac{-12}{13} \text { where } A \text { and } B \text { lie in first and third quadrant respectively. Then } \cos (A+B)= $$

A
$$ \frac{16}{65} $$
B
$$ \frac{-56}{65} $$
C
$$ \frac{56}{65} $$
D
$$ \frac{-16}{65} $$
2
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$\cos A=m \cos B$$ and $$\cot \left(\frac{A+B}{2}\right)=\lambda \tan \left(\frac{B-A}{2}\right)$$, then $$\lambda$$ is equal to

A
$$\frac{m}{m-1}$$
B
$$\frac{m+1}{m}$$
C
$$\frac{m+1}{m-1}$$
D
None of these
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The expression $$\frac{2 \tan A}{1-\cot A}+\frac{2 \cot A}{1-\tan A}$$ can be written as

A
$$\sin 2 A+\cos 2 A$$
B
$$2 \sec A \operatorname{cosec} A+2$$
C
$$\tan 2 A+\cot 2 A$$
D
$$\sec 2 A+\operatorname{cosec} 2 A$$
4
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \cos ^6 A-\sin ^6 A \text { is equal to } $$

A
$$ \cos 2 A\left(1-\frac{1}{4} \sin ^2 2 A\right) $$
B
$$ \cos 2 A\left(1-\frac{3}{4} \sin ^2 2 A\right) $$
C
$$ \cos 2 A\left(1-\frac{1}{2} \sin ^2 2 A\right) $$
D
$$ \cos 2 A\left(1+\frac{1}{4} \sin ^2 2 A\right) $$
COMEDK Subjects
EXAM MAP