$\text{Bp-Bp} > \text{Lp-Bp} > \text{Lp-Lp}$

$\text{Lp-Lp} > \text{Lp-Bp} > \text{Bp-Bp}$

$\text{Lp-Bp} > \text{Bp-Bp} > \text{Lp-Lp}$

$\text{Lp-Lp} > \text{Bp-Bp} > \text{Lp-Bp}$

$\text{NH}_3$ and $\text{NF}_3$ both are polar molecules

$\text{NH}_3$ and $\text{NF}_3$ both have pyramidal shape

In $\text{NH}_3$ and $\text{NF}_3$ the orbital dipole due to lone pair is in the same direction as that of resultant dipole moment of other three bonds

Dipole moment of $\text{NH}_3$ is greater than $\text{NF}_3$

$-2$

$+2$

$-1$

$0$

$\text{SnCl}_2$

$\text{PbCl}_4$

$\text{SbCl}_3$

$\text{PbCl}_2$