GATE ECE 1990 | GATE ECE Year Wise Previous Years Questions

GATE ECE 1990

MCQ (Single Correct Answer)

-0.6

The CMRR of the differential Amplifier of the fig is equal to GATE ECE 1990 Analog Circuits - Operational Amplifier Question 48 English

1000

900

1800

GATE ECE 1990

MCQ (Single Correct Answer)

-0.6

The Op-Amp of fig has a very poor open loop voltage gain of 45 but is otherwise ideal. The gain of the Amplifier equals: GATE ECE 1990 Analog Circuits - Operational Amplifier Question 47 English

4.5

GATE ECE 1990

MCQ (Single Correct Answer)

-0.6

If the input to the circuit of figure is a sine wave the output will be. GATE ECE 1990 Analog Circuits - Operational Amplifier Question 55 English

A half-wave rectified sine wave.

A full-wave rectified sine wave.

A triangular wave.

A square wave.

GATE ECE 1990

MCQ (Single Correct Answer)

-0.6

For good stabilized biasing of the transistor of the CE Amplifier of fig, we should have GATE ECE 1990 Analog Circuits - Bipolar Junction Transistor Question 18 English

GATE ECE 1990 Analog Circuits - Bipolar Junction Transistor Question 18 English

$${{{R_E}} \over {{R_B}}} < < 1$$

$${{{R_E}} \over {{R_B}}} > > 1$$

$${{{R_e}} \over {{R_B}}} < < {h_{FE}}$$

$${{{R_E}} \over {{R_B}}} > > {h_{FE}}$$

GATE ECE Papers

2024