1
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
The rate constant for a zero order reaction $\mathrm{A} \rightarrow \mathrm{B}+\mathrm{C}$ is $6.0 \times 10^{-3} \mathrm{molL}^{-1} \mathrm{~s}^{-1}$. What would be the time taken for the initial concentration of A to decrease from 0.2 M to 0.024 M ?
A
15.83 s
B
37.34 s
C
31.90 s
D
29.33 s
2
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two statements, One Assertion (A) and the other Reason (R) are given. Choose the right option.

Assertion: The rate constant $(\mathrm{k})$ for a chemical reaction gets nearly doubled for a $10^0$ rise in temperature.

Reason: The number of bimolecular collisions between reactant molecules increase with increase in temperature

A
A is correct but R is wrong.
B
Both A and R are correct but R is not the correct explanation of A .
C
Both $A$ and $R$ are correct and $R$ is the correct explanation of $A$.
D
A is wrong but R is correct.
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two chemical reactions of the same order have equal Frequency factor value. Their Activation energies differ by $26.8 \mathrm{~kJ} / \mathrm{mol}$. At 300 K if $k_2=x k_1$ find the value of $x$.
A
$4.631 \times 10^4$
B
$1.143 \times 10^3$
C
$2.286 \times 10^3$
D
4.665
4
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
For a given reaction of the type $\frac{3}{5} X(a q) \rightarrow \frac{1}{2} Y(a q)+Z(g)$, the correct expression for the rate of disappearance of $X$ with reference to $Y$ is ___________
A
$-d \frac{[X]}{d t}=+\frac{6}{5} d \frac{[Y]}{d t}$
B
$-d \frac{[X]}{d t}=+\frac{5}{6} d \frac{[Y]}{d t}$
C
$-d \frac{[X]}{d t}=+\frac{3}{10} d \frac{[Y]}{d t}$
D
$-d \frac{[X]}{d t}=d \frac{[Y]^{1 / 2}}{d t}$
COMEDK Subjects
EXAM MAP