COMEDK 2025 Evening Shift | Compounds Containing Nitrogen Question 12 | Chemistry

Assertion : Primary and secondary amides on treatment with $\mathrm{Br}_2$ and alcoholic NaOH yield primary and secondary amines respectively and the reaction involves stepping down the series.

Reason : The reaction occurs due to the migration of alkyl group from Carbonyl carbon atom to the Nitrogen atom with elimination of carbonyl group as the carbonate salt.

Assertion is correct but Reason is incorrect.

Both Assertion and Reason are incorrect.

Both Assertion and Reason are correct.

Assertion is incorrect but Reason is correct.

COMEDK 2025 Afternoon Shift

MCQ (Single Correct Answer)

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An organic compound $\mathrm{A}\left(\mathrm{C}_5 \mathrm{H}_9 \mathrm{~N}\right)$ upon reaction with $\mathrm{Na} / \mathrm{Hg} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$ gives compound B . B reacts with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at 274 K to form C with quantitative liberation of $\mathrm{N}_2$ gas. B also reacts with Hinsberg's reagent to form a compound which is soluble in alkali. Identify compound B.

$\left[\left(\mathrm{CH}_3\right)_3-\mathrm{N}-\mathrm{CH}_2 \mathrm{CH}_3\right]^{+}$

$\mathrm{CH}_3-\left(\mathrm{CH}_2\right)_3-\mathrm{NH}-\mathrm{CH}_3$

$\mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2$

$\mathrm{CH}_3-\left(\mathrm{CH}_2\right)_2-\mathrm{N}-\left(\mathrm{CH}_3\right)_2$

COMEDK 2025 Afternoon Shift

MCQ (Single Correct Answer)

-0

Identify the product $(\mathrm{Y})$ formed in the given reaction and the name of the reaction where $(\mathrm{X}) \rightarrow(\mathrm{Y})$.

COMEDK 2025 Afternoon Shift Chemistry - Compounds Containing Nitrogen Question 13 English

$Y=$ Ethoxybenzene $\quad$ Wurtz-Fittig reaction

$\mathrm{Y}=$ Diphenyl $\quad$ Fittig reaction

$\mathrm{Y}=1,4$ - Diiodobenzene $\quad$ Wurtz reaction

$Y=$ Iodobenzene $\quad$ Sandmeyer's reaction

COMEDK 2025 Afternoon Shift

MCQ (Single Correct Answer)

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Choose the correct statement:

Aliphatic amines are weaker bases than $\mathrm{NH}_3$ while aromatic amines are stronger bases than $\mathrm{NH}_3$.

Gabriel phthalimide synthesis is used for preparing both Ethyl amine and Aniline.

Anilinium ion is less resonance stabilised than Aniline.

Sec-butylamine is optically inactive because Nitrogen atom of the $-\mathrm{NH}_2$ group is achiral.

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