1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The width of the fringes obtained in the Young's double slit experiment is $$2.6 \mathrm{~mm}$$ when light of wave length $$6000^{\circ} \mathrm{A}$$ is used. If the whole apparatus is immersed in a liquid of refractive index 1.3 the new fringe width will be :

A
2.6 mm
B
5.2 mm
C
2 mm
D
4 mm
2
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a single slit diffraction experiment, for slit width '$$\alpha$$' the width of the central maxima is '$$\beta$$'. If we double the slit width then the corresponding width of the central maxima will be:

A
$$4 \beta$$
B
$$\beta$$
C
$$\frac{\beta}{2}$$
D
$$2 \beta$$
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit interference experiment, using two coherent waves of different amplitudes, the intensities ratio between bright and dark fringes is 3 . Then, the value of the ratio of the amplitudes of the wave that arrive there is

A
$$\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right)$$
B
$$\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)$$
C
$$\sqrt{3}: 1$$
D
$$1: \sqrt{3}$$
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is $$9: 1$$. The ratio of amplitudes of coherent sources is

A
$$9: 1$$
B
$$3: 1$$
C
$$2: 1$$
D
$$1: 1$$
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