COMEDK 2025 Morning Shift | Wave Optics Question 7 | Physics

In a single slit Fraunhofer diffraction pattern obtained at normal incidence, at the angular position of the second diffraction minimum the phase difference (in radian) between the waves from the opposite edges of the slit is

$\pi$

zero

$2\pi$

$\frac{\pi}{2}$

COMEDK 2025 Morning Shift

MCQ (Single Correct Answer)

-0

Two coherent waves of intensities $I_1$ and $I_2$ pass through a region at the same time in the same direction. The sum of maximum to minimum intensities is

$\left(I_1+I_2\right)$

$2\left(I_1+I_2\right)$

$2\left(\sqrt{I_1}+\sqrt{I_2}\right)^2$

$\left(I_1+I_2\right)^2$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

In Young's double slit experiment light of wavelength $$500 \mathrm{~nm}$$ is used to form interference pattern. A uniform glass plate of refractive index 1.5 and thickness $$0.1 \mathrm{~mm}$$ is introduced in the path of one of the interfering beams. The number of fringes that will shift due to this is

100

400

300

200

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Two narrow parallel slits illuminated by a coherent monochromatic light produces an interference pattern on a screen placed at a distance $$\mathrm{D}$$ from the slits. The separation between the dark lines of the interference pattern can be increased by

decreasing the distance between the screen and the slits

increasing the distance between the slits

using monochromatic light of a longer wavelength

using monochromatic light of higher frequency

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