COMEDK 2025 Morning Shift | Capacitor Question 1 | Physics

Two capacitors $\mathrm{C}_1$ and $\mathrm{C}_2$ are charged to 100 V and 120 V respectively. It is found that upon connecting them together in parallel, the potential on each one of them is zero. Therefore

$\mathrm{C}_1+3 \mathrm{C}_2=0$

$5 \mathrm{C}_1=3 \mathrm{C}_2$

$5 \mathrm{C}_1+6 \mathrm{C}_2=0$

$5 \mathrm{C}_1=6 \mathrm{C}_2$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Figure below shows a network of resistors, cells, and a capacitor at steady state.

COMEDK 2024 Evening Shift Physics - Capacitor Question 3 English

What is the current through the resistance 4 $$\Omega$$ ?

1.0 A

0.2 A

Zero

0.5 A

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

A parallel plate capacitor having a dielectric constant 5 and dielectric strength $$10^6 \mathrm{~V} \mathrm{~m}^{-1}$$ is to be designed with voltage rating of $$2 \mathrm{~kV}$$. The field should never exceed $$10 \%$$ of its dielectric strength. To have the capacitance of $$60 \mathrm{~pF}$$ the minimum area of the plates should be

$$27.1 \times 10^{-4} \mathrm{~m}^2$$

$$2.7 \times 10^{-2} \mathrm{~m}^2$$

$$2.71 \times 10^{-4} \mathrm{~m}^2$$

$$27.1 \times 10^{-2} \mathrm{~m}^2$$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

The figure shows a network of five capacitors connected to a 20 V battery. Calculate the charge acquired by each 10 $$\mu$$F capacitor.

COMEDK 2024 Evening Shift Physics - Capacitor Question 2 English

$$2 \times 10^{-4} \mathrm{C}$$

$$4 \times 10^{-4} \mathrm{C}$$

$$6 \times 10^{-4} \mathrm{C}$$

$$1 \times 10^{-4} \mathrm{C}$$

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