COMEDK 2023 Evening Shift | Current Electricity Question 3 | Physics

The current sensitivity of a galvanometer having 20 divisions is $$10 \mu \mathrm{A} /$$ div. If the resistance of the galvanometer is $$100 \Omega$$ then the value of the resistance to be used to convert this galvanometer in to an voltmeter to read up to $$1 \mathrm{~V}$$ is :

$$4 \times 10^{-6} \Omega$$ in series with the galvanometer.

$$4900 \Omega$$ in parallel with the galvanometer.

$$4 \times 10^{-3} \Omega$$ in series with the galvanometer.

$$4900 \Omega$$ in series with the galvanometer.

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

The electric flux from cube of side $$1 \mathrm{~m}$$ is '$$\Phi$$' When the side of the cube is made $$3 \mathrm{~m}$$ and the charge enclosed by the cube is made one third of the original value, then the flux from the bigger cube will be :

$$\frac{\Phi}{3}$$

$$\Phi$$

$$3 \Phi$$

$$9 \Phi$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

A resistor of wire $$24 \mathrm{~cm}$$ length and resistance $$8 \Omega$$ is stretched in to a uniform wire of $$48 \mathrm{~cm}$$ length, then the new resistance will be :

$$32 \Omega$$

$$8 \Omega$$

$$16 \Omega$$

$$4 \Omega$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

The SI unit of electrical conductivity is :

S m

$$\Omega \mathrm{~m}$$

$$\mathrm{S} \mathrm{~m}^{-1}$$

$$\Omega \mathrm{~m}^{-1}$$

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