In Friedal-Crafts alkylation reaction of phenol with chloromethane, the product formed will be
Identify A, B and C.
Identify the compounds A, B, C and D.
$$ \text { 1,2,2,2-tetrachloroethane } \xrightarrow[\Delta]{\mathrm{Zn}}[\mathrm{A}] $$
[A] $$ \xrightarrow[675 \mathrm{~K}]{\text { Fe tube }} $$ [B] $$ \xrightarrow[\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4]{\text { Conc. } \mathrm{HNO}_3} $$ [C] $$ \xrightarrow[\text { Anhydrous } \mathrm{AlCl}_3]{\mathrm{Cl} /}$$ [D]
The reactions taking place with $$\mathrm{2- Phenyl-2-bromopropane}$$ as the starting material is shown below. Identify [A] and [B] formed in the reaction.
$$ \mathrm{C}_6 \mathrm{H}_5-\mathrm{C}\left(\mathrm{CH}_3\right)_2^{-} \mathrm{Br} \xrightarrow[\Delta]{\text { KOH Alcoholic }}[\mathrm{A}] $$
$$ [\mathrm{A}]+\mathrm{HBr} \xrightarrow{\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO})_2 \mathrm{O}\right.}[\mathrm{B}]$$