If the equation of the plane passing through the point $(3,2,5)$ and perpendicular to the planes $2 x-3 y+5 z=7$ and $5 x+2 y-3 z=11$ is $x+b y+c z+d=0$, then $2 b+3 c+d=$

The circumradius of the triangle formed by the points $(2,-1,1),(1,-3,-5)$ and $(3,-4,-4)$ is

Let $A(2,3,5), B(-1,3,2)$ and $C(\lambda, 5, \mu)$ be the vertices of $\triangle A B C$. If the median through the vertex $A$ is equally inclined to the coordinate axes, then

Equation of the plane passing through the origin and perpendicular to the planes $x+2 y-z=1$ and $3 x-4 y+z=5$ is