1
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Assertion (A) For the lines $\mathbf{r}=\mathbf{a}+t \mathbf{b}$ and $\mathbf{r}=\mathbf{p}+s \mathbf{q}$, if $(\mathbf{a}-\mathbf{p}) \cdot(\mathbf{b} \times \mathbf{q}) \neq 0$, then the two lines are coplanar.

Reason $(\mathrm{R})|(\mathbf{a}-\mathbf{p}) \cdot(\mathbf{b} \times \mathbf{q})|$ is $|\mathbf{b} \times \mathbf{q}|$ times the shortest distance between the lines $\mathbf{r}=\mathbf{a}+t \mathbf{b}$ and $\mathbf{r}=\mathbf{p}+s \mathbf{q}$.

A

(A) is true, (R) is true and (R) is correct explanation to (A)

B

(A) is true, (R) is true and (R) is not the correct explanation to (A)

C

(A) is true, (R) is false

D

(A) is false, (R) is true

2
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The locus of a point at which the line joining the points $(-3,1,2),(1,-2,4)$ subtends a right angle, is

A

$x^2+y^2+z^2+2 x+y-6 z-3=0$

B

$x^2+y^2+z^2+2 x-y-6 z+3=0$

C

$x^2+y^2+z^2+2 x+y-6 z+3=0$

D

$x^2+y^2+z^2-2 x+y-6 z+3=0$

3
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $A(1,2,3), B(2,3,-1), C(3,-1,-2)$ are the vertices of a $\triangle A B C$, then the direction ratios of the bisector of $\angle A B C$ are

A

$(4,1,1)$

B

$(3,5,2)$

C

$(1,4,1)$

D

$(2,-3,-5)$

4
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $A=(2,0,-1), B=(1,-2,0), C=(1,2,-1)$ and $D=(0,-1,-2)$ be four points.

If $\theta$ is the acute angle between the plane determined by $A, B, C$ and the plane determined by $A, C, D$, then $\tan \theta=$

A

$\sqrt{\frac{14}{5}}$

B

$\frac{3}{\sqrt{14}}$

C

$\frac{3}{\sqrt{5}}$

D

$\frac{\sqrt{5}}{3}$

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