Variance of the following continuous frequency distribution is

$$ \begin{array}{cc} \hline \text { Class Interval } & \text { Frequency } \\ \hline 0-4 & 1 \\ \hline 4-8 & 2 \\ \hline 8-12 & 2 \\ \hline 12-16 & 1 \\ \hline \end{array} $$

If $\sum_{i=1}^9\left(x_i-5\right)=9$ and $\sum_{i=1}^9\left(x_i-5\right)^2=45$, then the standard deviation of the nine observations $x_1, x_2, \ldots, x_9$ is

The mean deviation from the median for the following data is

$$ \begin{array}{llllll} \hline x_1 & 9 & 3 & 7 & 2 & 5 \\ \hline f_1 & 1 & 6 & 2 & 8 & 4 \\ \hline \end{array} $$

The mean deviation about the mean for the following data is

$$ \begin{array}{llllll} \hline \text { Class Interval } & 0-2 & 2-4 & 4-6 & 6-8 & 8-10 \\ \hline \text { Frequency } & 1 & 3 & 4 & 1 & 2 \\ \hline \end{array} $$