The area (in sq units) of the region given by $R=\left\{(x, y) ; \frac{y^2}{2} \leq x \leq y+4\right\}$ is

The area of the region (in sq units) bounded by the curves $x^2+y^2=16$ and $y^2=6 x$ is

The area (in sq. units) of the region bounded by the curves $y=x^2$ and $y=8-x^2$ is

Area of the region (in sq. units) bounded by the curve $y=x^2-5 x+4, x=0, x=2$ and the $X$-axis is