Area Under The Curves · Mathematics · AP EAPCET
MCQ (Single Correct Answer)
The area (in sq units) of the region given by $R=\left\{(x, y) ; \frac{y^2}{2} \leq x \leq y+4\right\}$ is
The area of the region (in sq units) bounded by the curves $x^2+y^2=16$ and $y^2=6 x$ is
The area (in sq. units) of the region bounded by the curves $y=x^2$ and $y=8-x^2$ is
Area of the region (in sq. units) bounded by the curve $y=x^2-5 x+4, x=0, x=2$ and the $X$-axis is
The area of the region lying between the curves $y=\sqrt{4-x^2}, y^2=3 x$ and the $Y$-axis is
The area of the region (in sq. units) enclosed between the curves $y=|x|, y=[x]$ and the ordinates $x=-1$, $x=0, x=1$ is
If $(a, \beta)$ is the stationary point of the curve $y=2 x-x^2$, then the area bounded by the curves $y=2^x, y=2 x-x^2, x=0$ and $x=\alpha$ is