1
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Identify the final product formed when benzenamine reacts with the given reagents in the sequential order as:

i. $\quad\left(\mathrm{CH}_3-\mathrm{CO}\right)_2 \mathrm{O} /$ Pyridine.

ii.      Conc. $\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{SO}_4$ \& then reacted with $\mathrm{H}_3 \mathrm{O}^{+}$

iii. $\quad \mathrm{NaNO}_2 \mathrm{HCl}(273 \mathrm{~K})$ \& then reacted with $\mathrm{H}_3 \mathrm{PO}_2(\mathrm{aq})$.

A

2- Chloro- 4-Nitrophenol

B

4-Chloro-2-Nitroaniline

C

Nitrobenzene

D

4-Nitrophenol

2
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { Identify the correct order of the type of reactions taking place in this sequence: } $$

COMEDK 2026 Morning Shift Chemistry - Compounds Containing Nitrogen Question 4 English
A

Reduction, Diazotization, Coupling

B

Oxidation, Coupling, Diazotization

C

Reduction, Diazotization, Addition

D

Reduction, Coupling, Diazotization

3
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The reagent used in carbylamine reaction is $\_\_\_\_$ and the product of the reaction will be $\_\_\_\_$

A

Alcoholic $\mathrm{KOH}+\mathrm{CHCl}_3$; isocyanide

B

Benzene sulphonyl chloride ; sulphonamide

C

Alcoholic $\mathrm{KOH}+\mathrm{CHCl}_3$; cyanide

D

Concentrated $\mathrm{HCl}+\mathrm{NaNO}_2$; diazonium salt

4
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Which of the following is the correct reaction of Hinsberg's reagent with primary, secondary and tertiary amines?

A

Primary amine forms N , N -dialkyl Benzene sulphonamide which is soluble in alkali

B

Tertiary amine forms N, N-dialkyl Benzene sulphonamide which is insoluble in alkali

C

Secondary amine forms N, N-dialkyl Benzene sulphonamide which is soluble in alkali

D

Primary amine forms N -alkyl Benzene sulphonamide which is soluble in alkali

COMEDK Subjects

Browse all chapters by subject