1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

An unsaturated hydrocarbon $$[\mathrm{A}]$$ reacts with $$\mathrm{HBr}$$ in presence of Benzoyl peroxide to yield [B] Compound [A] when reacted with cold, dilute alkaline $$\mathrm{KMnO}_4$$ gave compound [C], 2-Methylbutane-2, 3-diol But when [A] is reacted with hot $$\mathrm{KMnO}_4$$, it yielded $$\mathrm{CH}_3 \mathrm{COOH}$$ and a compound [D] Identify compounds [A], [B] and [D]

A
[A] 3-Methylbut-1-ene [B] 1-Bromo-3-methylbutane [D] Propanoic acid.
B
[A] Pent-2-ene [B] 2-Bromopentane [D] Propanal
C
[A] 2-Methylbut-2-ene [B] 2-Bromo-3-methylbutane [D] Propanone
D
[A] Pent-1-ene [B] 1-Bromopentane [D] Propanoic acid
2
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

An aromatic hydrocarbon $$[\mathrm{A}]\left(\mathrm{Molecular}\right.$$ formula $$\left.\mathrm{C}_9 \mathrm{H}_{12}\right)$$, undergoes air oxidation followed by reaction with dil. $$\mathrm{HCl}$$ to give [B] as one of the products

Compound [B] forms a white precipitate on treatment with $$\mathrm{Br}_2(\mathrm{aq})$$

Sodium salt of [B] reacts with $$\mathrm{CO}_2$$ at $$400 \mathrm{~K}$$ under high pressure followed by acid hydrolysis to give [C]

Compound [C] reacts with acetic anhydride / conc. $$\mathrm{H}_2 \mathrm{SO}_4$$ to form [D] Identify compound $$[\mathrm{D}]$$

A
COMEDK 2024 Morning Shift Chemistry - Hydrocarbons Question 17 English Option 1
B
COMEDK 2024 Morning Shift Chemistry - Hydrocarbons Question 17 English Option 2
C
COMEDK 2024 Morning Shift Chemistry - Hydrocarbons Question 17 English Option 3
D
COMEDK 2024 Morning Shift Chemistry - Hydrocarbons Question 17 English Option 4
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Ammoniacal silver nitrate forms a white precipitate easily with

A
$$\mathrm{CH}_3 \mathrm{C}=\mathrm{CH}$$
B
$$\mathrm{CH}_3 \mathrm{C}=\mathrm{CCH}_3$$
C
$$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2$$
D
$$\mathrm{CH}_2=\mathrm{CH}_2$$
4
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The conversion of Propyne to Benzene can be brought out in 4 steps.

Choose the reagents to be used, in the proper sequential order, to bring out the conversion.

Reagents provided: alc. $$\mathrm{KOH}, \mathrm{H}_2 / \mathrm{Pd}, \mathrm{Na} /$$ dry ether, $$\mathrm{HBr}, \mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2$$, Soda-lime, $$\mathrm{Cr}_2 \mathrm{O}_3$$ (high T and P), Conc. $$\mathrm{H}_2 \mathrm{SO}_4$$

A
$$\mathrm{Na} /$$ Ether, $$\mathrm{Cr}_2 \mathrm{O}_3$$ (high $$\mathrm{T}$$ and $$\mathrm{P}$$), $$\mathrm{HBr}, \mathrm{H}_2 / \mathrm{Pd}$$
B
$$\mathrm{HBr}$$, alc. $$\mathrm{KOH}, \mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2, \mathrm{Cr}_2 \mathrm{O}_3$$ (high $$\mathrm{T}$$ and $$\mathrm{P}$$)
C
$$\mathrm{Cr}_2 \mathrm{O}_3$$ (high $$\mathrm{T}$$ and $$\mathrm{P}$$), $$\mathrm{Na} /$$ dry ether, $$\mathrm{HBr}$$, Conc. $$\mathrm{H}_2 \mathrm{SO}_4$$
D
$$\mathrm{H}_2 / \mathrm{Pd}, \mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2, \mathrm{Na} /$$ dry ether, $$\mathrm{Cr}_2 \mathrm{O}_3$$ (high $$\mathrm{T}$$ and $$\mathrm{P}$$)
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