COMEDK 2024 Morning Shift | Circular Motion Question 4 | Physics

A metal ball of $$20 \mathrm{~g}$$ is projected at an angle $$30^{\circ}$$ with the horizontal with an initial velocity $$10 \mathrm{~ms}^{-1}$$. If the mass and angle of projection are doubled keeping the initial velocity the same, the ratio of the maximum height attained in the former to the latter case is :

1 : 2

2 : 1

1 : 3

3 : 1

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

A body is moving along a circular path of radius '$$r$$' with a frequency of revolution numerically equal to the radius of the circular path. What is the acceleration of the body if radius of the path is $$\left(\frac{5}{\pi}\right) m$$ ?

$$ 100 \pi \mathrm{~ms}^{-2} $$

$$ 500 \pi \mathrm{~ms}^{-2} $$

$$ 25 \pi \mathrm{~ms}^{-2} $$

$$ \left(\frac{500}{\pi}\right) \mathrm{ms}^{-2} $$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

One end of the string of length $l$ is connected to a particle of mass $$m$$ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed $$v$$, the net force on the particle (directed towards centre) will be ( $$T$$ represents the tension in the string)

$$T$$

$$T+\frac{m v^2}{l}$$

$$T-\frac{m v^2}{l}$$

zero

COMEDK 2021

MCQ (Single Correct Answer)

-0

When a car of mass $$m$$ is moving with speed $$v$$ along a circle of radius $$r$$ on a level road, the centripetal force is provided by $$f$$, where $$f$$ denotes

($$\mu_s$$ $$\to$$ coefficient of friction, N $$\to$$ normal reaction)

$${{m{v^2}} \over r} = f \le {\mu _s}N$$

$$f < {\mu _s} = {{m{v^2}} \over r}$$

$$f = {\mu _s}N = {{m{v^2}} \over r}$$

$$f = {\mu _k}N = {{m{v^2}} \over r}$$

COMEDK Subjects