COMEDK 2025 Afternoon Shift | Circular Motion Question 1 | Physics

A coin is placed on a disc rotating with an angular velocity $\omega$. The co-efficient of friction between the disc and the coin is $\mu$. The maximum distance of the coin from the centre of the disc up to which it will rotate with the disc is

$\sqrt{\frac{\mu}{\omega^2}}$

$\frac{\mu g}{\omega^2}$

$\sqrt{\frac{\mu g}{\omega^2}}$

$\frac{\mu g}{\omega}$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

A ball is moving in a circular path of radius $$5 \mathrm{~m}$$. If tangential acceleration at any instant is $$10 \mathrm{~ms}^{-2}$$ and the net acceleration makes an angle of $$30^{\circ}$$ with the centripetal acceleration, then, the instantaneous speed is

$$5.4 \mathrm{~ms}^{-1}$$

$$50 \sqrt{3} \mathrm{~ms}^{-1}$$

$$6.6 \mathrm{~ms}^{-1}$$

$$9.3 \mathrm{~ms}^{-1}$$

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

A metal ball of $$20 \mathrm{~g}$$ is projected at an angle $$30^{\circ}$$ with the horizontal with an initial velocity $$10 \mathrm{~ms}^{-1}$$. If the mass and angle of projection are doubled keeping the initial velocity the same, the ratio of the maximum height attained in the former to the latter case is :

1 : 2

2 : 1

1 : 3

3 : 1

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

A body is moving along a circular path of radius '$$r$$' with a frequency of revolution numerically equal to the radius of the circular path. What is the acceleration of the body if radius of the path is $$\left(\frac{5}{\pi}\right) m$$ ?

$$ 100 \pi \mathrm{~ms}^{-2} $$

$$ 500 \pi \mathrm{~ms}^{-2} $$

$$ 25 \pi \mathrm{~ms}^{-2} $$

$$ \left(\frac{500}{\pi}\right) \mathrm{ms}^{-2} $$

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