1
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
Applying a constant torque the speed of a flywheel is increased from 1800 rpm to 2400 rpm in 10 seconds. The number of revolutions made by the flywheel during this time is:
A
350
B
900
C
700
D
2100
2
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
A bullet of momentum $p$ is fired into a door and gets embedded exactly at the center of the door. The door is 1.0 m wide and weighs 12 kg . It is hinged at one end and rotates about a vertical axis practically without friction. The angular speed of the door just after the bullet embeds into it is :
A
$\frac{p}{4}$
B
$\frac{3 p}{5}$
C
$\frac{p}{8}$
D
$\frac{3}{8 p}$
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
A force of $-\mathrm{F} \hat{\mathbf{i}}$ acts at the origin of the coordinate system. The torque about the point $(0,1,-1)$ is:
A
$F(\hat{\jmath}+\hat{\mathrm{k}})$
B
$-F(\hat{\jmath}+\mathrm{k})$
C
$F(\hat{\mathrm{i}}+\mathrm{k})$
D
$-F(\hat{\imath}+\hat{\jmath})$
4
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

A solid cylinder of mass $$2 \mathrm{~kg}$$ and radius $$0.2 \mathrm{~m}$$ is rotating about its own axis without friction with angular velocity $$5 \mathrm{~rad} \mathrm{s}^{-1}$$. A particle of mass $$1 \mathrm{~kg}$$ moving with a velocity of $$5 \mathrm{~ms}^{-1}$$ strikes the cylinder and sticks to it as shown in figure.

COMEDK 2024 Evening Shift Physics - Rotational Motion Question 4 English

The angular velocity of the system after the particle sticks to it will be

A
$$ 15.0 \mathrm{~rad~s}^{-1} $$
B
$$ 12.0 \mathrm{~rad~s}^{-1} $$
C
$$ 10.0 \mathrm{~rad~s}^{-1} $$
D
$$ 30.0 \mathrm{~rad~s}^{-1} $$
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