COMEDK 2025 Afternoon Shift | Rotational Motion Question 2 | Physics

A bullet of momentum $p$ is fired into a door and gets embedded exactly at the center of the door. The door is 1.0 m wide and weighs 12 kg . It is hinged at one end and rotates about a vertical axis practically without friction. The angular speed of the door just after the bullet embeds into it is :

$\frac{p}{4}$

$\frac{3 p}{5}$

$\frac{p}{8}$

$\frac{3}{8 p}$

COMEDK 2025 Morning Shift

MCQ (Single Correct Answer)

-0

A force of $-\mathrm{F} \hat{\mathbf{i}}$ acts at the origin of the coordinate system. The torque about the point $(0,1,-1)$ is:

$F(\hat{\jmath}+\hat{\mathrm{k}})$

$-F(\hat{\jmath}+\mathrm{k})$

$F(\hat{\mathrm{i}}+\mathrm{k})$

$-F(\hat{\imath}+\hat{\jmath})$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

A solid cylinder of mass $$2 \mathrm{~kg}$$ and radius $$0.2 \mathrm{~m}$$ is rotating about its own axis without friction with angular velocity $$5 \mathrm{~rad} \mathrm{s}^{-1}$$. A particle of mass $$1 \mathrm{~kg}$$ moving with a velocity of $$5 \mathrm{~ms}^{-1}$$ strikes the cylinder and sticks to it as shown in figure.

COMEDK 2024 Evening Shift Physics - Rotational Motion Question 4 English

The angular velocity of the system after the particle sticks to it will be

$$ 15.0 \mathrm{~rad~s}^{-1} $$

$$ 12.0 \mathrm{~rad~s}^{-1} $$

$$ 10.0 \mathrm{~rad~s}^{-1} $$

$$ 30.0 \mathrm{~rad~s}^{-1} $$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Joule second is the unit of

Energy

Power

Angular momentum

Linear momentum

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